Название: Liquid Crystals
Автор: Iam-Choon Khoo
Издательство: John Wiley & Sons Limited
Жанр: Техническая литература
isbn: 9781119705796
isbn:
(2.24a)
Figure 2.6. Free energies F(Q) for different temperatures T. At T = Tc, ∂F/∂Q = 0 at two values of Q, where F has two stable minima. On the other hand, at
(i.e. with some alignment of the molecule in the z direction) is not the same as the state with a negative Q parameter
(2.24b)
(which signifies some alignment of the molecules in the x‐y plane).
The cubic term in F is also important in that it dictates that the phase transition at T = Tc is of the first order (i.e. the first‐order derivative of F, ∂F/∂θ, is vanishing at T = Tc, as shown in Figure 2.6). The system has two stable minima, corresponding to Q = 0 or Q ≠ 0 (i.e. the coexistence of the isotropic and nematic phases). On the other hand, for
2.4.2. Free Energy in the Presence of an Applied Field
In the presence of an externally applied field (e.g. dc or low‐frequency electric, magnetic, or optical electric field), a corresponding interaction term should be added to the free energy.
For an applied magnetic field H, the energy associated with it is
(2.25)
where M is the magnetization given by
(2.26)
Thus
(2.27)
Using Eq. (2.9), we can rewrite Fint as
The first term on the right‐hand side of Eq. (2.28) is independent of the orientation of the (anisotropic) molecules, and it can therefore be included in the constant F0.
On the other hand, the second term is dependent on the orientation of the molecules. Using Eq. (2.10) for the order parameter Qαβ we can write it as
(2.29)
Therefore, the total free energy of a liquid crystal in the isotropic phase, under the action of an externally applied magnetic field, is given by
(2.30)
Without solving the problem explicitly, we can infer from the magnetic interaction term that a lower energy state corresponds to some alignment of the molecules in the direction of the magnetic field (for Δχ m > 0).
Using a similar approach, we can also deduce that the electric interaction contribution to the free energy is given by (in inks units)
(2.31)
The orientation‐dependent term is therefore
(2.32)